Given the following mixture of two compounds 20.00 g of X (MW =83.00 g/mol) and 880.00 mL of Y (72.00 g/mol))(density 0.881 g/mL), calculate the molarity of X.
The molarity is the number of moles of solute per litre of solution: "molarity=n(solute)\/V(solution)"
In our case compound X is solute. First we calculate the number of moles of X:
"n(X)=m\/MW=20\/83=0.241~mol"
Volume of solution is the available volume of compound Y (in litres):
"V=880~ml=0.880~L"
"molarity=0.241\/0.880=0.274~mol\/L"
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