Question #130188

Solutions of sodium hydroxide (volume = 90.0 mL) and nitric acid (volume = 95.0 mL) were mixed together in a neutralization reaction.

Calculate the mass of the combined solution.

We can assume the density of the solution to be the same as water, 1.00 g/cm3.


Give you answer to three significant figures.



Expert's answer

Volume of Sodium Hydroxide =90.0 ml=90.0\ ml

Volume of Nitric Acid=95.0 ml=95.0 \ ml

Total Volume =(90.0+95.0) ml=185 ml=(90.0+95.0)\ ml=185\ ml

Density of solution =1.00 g/cm3=1.00 g/ml (∵1cm3=1 ml)= 1.00\ g/cm^3=1.00\ g/ml\ (\because 1 cm^3=1\ ml)

Mass of solution will be =V×ρ=185×1.00 g=185.00 g= V\times\rho=185\times 1.00 \ g= 185.00\ g

=185 g=185 \ g (In three significant figures)


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