Answer to Question #127764 in General Chemistry for Kayla

Question

In 25 grams of a 7.5% by mass solutions of CaSO4
1.) how many grams of solute are present
2.) how many grams of solvent are present

Answer 1

Solution

1.Wt. Of solute in gm. = (25*7.5)/100

= 1.875 gm.

2. Since wt. of solution = wt. of solute + wt. of solvent

Wt. of solution = 100 gm.

Wt. of solvent in gm. = 100 - 1.875

=98.125 gm.