Solution.
"\\nu(NaHCO3) = 3.75 \\ mol"
"\\nu(H2SO4) = 2.11 \\ mol"
"\\nu(NaHCO3)>\\nu(H2SO4)"
"\\nu(H2SO4) = \\nu(CO2) = 2.11 \\ mol"
"p \\times V = n \\times R \\times T"
"V = \\frac{n \\times R \\times T}{p}"
"V = 0.05234 m^3 = 52.34 \\ L"
Answer:
V = 52.34 L
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