how much temperature does it take to boil 17 grams of ammonia in 500 grams of water
Moles of NH3 = 17 / 17 = 1 mole .
Molality = moles / mass of solvent in kg .
Molality = 1 mol . / 0.5 kg .= 2 mol /kg . = m .
elevation in boilling point = (Kb ) * m ;
elevation in boilling point = ( 0.512 ) * 2 = 1.024 k .
boilling point of solution = ( 373 + 1.024 ) k .
So , boilling point of solution = 101.024 k . Answer .
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