Molarity=mole of solute/volume of solution in L
Mole of glucose=130mg*1g/1000mg*1mole/180.16g=7.22*10^-4 mol
Volume of solution in L=100mL*1L/1000mL=0.1L
Molarity=7.22*10^-4mol/0.1L=7.22*10^-3mol/L
85mL/kg*80kg=6800mL=6.8L
Mole of glucose=6.8L*7.22*10^-3mol/L=0.0491mol
Mass of glucose=0.0491mol*180.16g/mol=8.85g
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