Answer to Question #127559 in General Chemistry for mike

Question #127559

Calculate the volume of 0.02 mol L-1 potassium permanganate, KMnO4, solution that contains 1.0 X 10-3 mol of potassium permanganate.

Expert's answer

concentration = amount in solute/volume

0.02 = 1.0 *10-3/ volume

therefore volume = 1.0* 10-3/0.02

0.003/0.02 = 0.15 dm3

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