Answer to Question #126763 in General Chemistry for Connor Clemens

Question

21.0 mL of a pure, water-soluble liquid alcohol with a density of 1.219 g/mL is diluted with water, and the final mass of the solution is 5.00 × 102 g. What is the mass percent of the alcohol in this solution?

Answer 1

Mass percentage= mass of component/total mass of mixture x100

The mass of the liquid = density of liquid/volume of liquid

1.219/21=0.058g

Percentage mass= 0.058/510 where 510 is the mass of total mixture x100

Percentage mass =0.0001137 x 100= 0.01137%