Question #126364
The equivalence point happens when 36.0 mL of base has been added. If the pH when 18.0 mL of base has been added is 4.25, what is the value of Ka for this weak acid?
1
Expert's answer
2020-07-15T06:42:01-0400

At half equivalence point:

pH = pKa

4.25 = -logKa

Ka = 5.62×10-5 (Answer)

The value of Ka for this weak acid is 5.62×10-5.



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