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Answer to Question #126364 in General Chemistry for jake
Question #126364
The equivalence point happens when 36.0 mL of base has been added. If the pH when 18.0 mL of base has been added is 4.25, what is the value of Ka for this weak acid?
Expert's answer
At half equivalence point:
pH = pKa
4.25 = -logKa
Ka = 5.62×10-5 (Answer)
The value of Ka for this weak acid is 5.62×10-5.
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