Answer to Question #126236 in General Chemistry for tasnim

Question

1 g of NAOH is added to 30 cm3 of 1 M HCL. How many cubic cm of 0.1 KOH will be needed to neutralize excess acid

Answer 1

Molecular weight of NaOH is 40 g/mol

Moles of NaOH added = 1/40 mol = 0.025 mol

Strength of NaOH is = (0.025 ×1000)/30 = 0.8333 M

Excess acid presence = (1-0.833) M = 0.1667 M in 30 cm³

V₁S₁=V₂S₂

V₁ = (0.1667×30 )/0.1 = 50.01 cm³

50.01 cm³ KOH will be needed to neutralize excess acid.