If the heat of combustion for the reaction of Octane is -5471kj/mol, how much heat, in kj, is produced when one gallon of octane is burned in excess oxygen if the reaction works perfectly? Please report your answer in six significant figures.
1 gallon = 3.785 l
n = 3.785 / 22.4 = 0.1690 mol
Q = 0.1690 × 5471 = 924.5 kJ
Answer: 924.5 kJ.
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