"Reaction\\newline C3H8\\space+5O2\\space \\to\\space 3CO2\\space +4H2O.\\newline Mole \\space ratio \\newline1:5\\space\\to3:4\\space\\space therefore,\\newline No.\\space moles\\space of\\space water(H2O)=2.4*4=9.6mol\\newline In\\space1mol\\space of\\space H2O\\space there\\space are\\space 2\\space hydrogen \\space atoms\\space so\\space in \\space 9.6mol\\space we\\space have\\newline9.6mole*\\dfrac{6.02*10^{23}molec}{1mol}*\\dfrac{2atoms}{1molec}=1.15584*10^{25}"
"=""1.6*10^{25} \\space atoms"
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