Question #123154
1.00 L of helium gas in a cylinder at 56 800 kPa pressure fills a balloon at 163 kPa at the same temperature. What is the volume of the balloon?
1
Expert's answer
2020-06-22T09:17:18-0400

Boyles law is a gas law and it states that the pressure of a given mass of an idealgas is inversely propotional to its volume when temperature is kept constant.Therefore,  P1V1=P2V2  V2=P1V1P2Convert pressure into atmospheric pressure.1kPa=0.009869atm.56800kPa=??=560.6atm1kPa=0.009869atm163kPa=??=1.6atm  V2=560.611.6  V2=350.3LBoyle's\space law\space is \space a\space gas\space law\space and\space it\space states\space that\space the\space pressure\space of\space a\space given\space mass\space of\space an\space ideal\newline gas\space is\space inversely\space propotional\space to\space its\space volume\space when\space temperature\space is\space kept\space constant. \newline \newline Therefore,\newline\space\space P1V1=P2V2\newline\space\space V2=\dfrac{P1V1}{P2}\newline Convert\space pressure\space into\space atmospheric\space pressure.\newline 1kPa=0.009869atm.\newline56800kPa=??\newline=560.6atm\newline1kPa=0.009869atm\newline163kPa=??\newline=1.6atm\newline \space\space V2=\dfrac{560.6*1}{1.6} \newline \space\space V2=350.3L


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