Question

If a 10.0 kg tank of propane is completely consumed, what total mass of product is produced?

Answer 1

Ans.

The balanced combustion reaction for propane is

C₃H₈(g)+5O₂(g)→3CO₂(g)+4H₂O(g).

So, 1 mole of propane produces 3 moles of CO₂ and 4 moles of H₂O

Mole number of 10 kg propane is (10x10³)/44.1 = 226.75 moles (Considering molecular weight of propane =  44.1 gm)

So, 226.75 moles of propane will produce (3 x 226.75) moles of CO₂ and (4 x 226.75) moles of H₂O

1 mole of CO₂ = 44 gm CO₂

So, (3 x 226.75) moles of CO₂ = (44x3x226.75) gm CO₂ = 29.931 kg CO₂

 1 mole of H₂O = 18 gm H₂O

So, (4 x 226.75) moles of H₂O = (18x4x226.75) gm CO₂ = 16.321 kg H₂O

Total mass of product produced = (29.931 + 16.321) kg = 46.252 kg (Ans.)