Ans.
The balanced combustion reaction for propane is
C3H8(g)+5O2(g)→3CO2(g)+4H2O(g).
So, 1 mole of propane produces 3 moles of CO2 and 4 moles of H2O
Mole number of 10 kg propane is (10x103)/44.1 = 226.75 moles (Considering molecular weight of propane = 44.1 gm)
So, 226.75 moles of propane will produce (3 x 226.75) moles of CO2 and (4 x 226.75) moles of H2O
1 mole of CO2 = 44 gm CO2
So, (3 x 226.75) moles of CO2 = (44x3x226.75) gm CO2 = 29.931 kg CO2
1 mole of H2O = 18 gm H2O
So, (4 x 226.75) moles of H2O = (18x4x226.75) gm CO2 = 16.321 kg H2O
Total mass of product produced = (29.931 + 16.321) kg = 46.252 kg (Ans.)
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