Answer to Question #122774 in General Chemistry for Izzy

Question

What mass of carbon dioxide can be expected from a complete combustion of 1000.00 kg of propane with 1000.00 kg of oxygen?
If the percent yield for your reaction and collection technique is 72.5%, then how much carbon dioxide was actually created?

Answer 1

combustion reaction for propane:

C₃H₈+5O₂--->3CO₂+4H₂O

moles of propane taken = 1000000g/44gmol^-1

= 22727.27 moles

moles of oxygen taken = 1000000/32

= 31250 moles

here limiting reagent is oxygen so whole oxygen will be consumed.

no. of moles of carbon dioxide formed = (3/5)*31250

=18750 moles

since yield is 75% so obtained CO₂ is (75/100)*18750

= 14062.5 moles

mass of CO₂ obtained= 14062.5*44 g

=618750 grams = 618.750 kg