Mg+2HCl--->MgCl2+H2
moles of magnesium taken = 7.15/24 = 0.297 moles
moles of HCl taken = 8/36.5= 0.219 moles
here limiting reagent is HCl so whole HCl will be consumed. so accordingly
moles of H2 produced is half of moles of HCl
moles of H2= (1/2)*0.219 moles= 0.1095 moles
1 mole at STP corresponds 22.4L
so 0.1095 moles of H2 at STP is 22.4*0.1095 L
=2.458L
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