Answer to Question #122062 in General Chemistry for sonia

Question

You are creating a precipitate of silver chloride,starting with 1.00 mol of silver nitrate and 0.75 mol of potassium chloride ( AgNO₃ + KCl → AgCl + KNO₃). What is the maximum amount of silver chloride that can be produced?

Answer 1

AgNO₃+ KCl= AgCl+ KNO₃

As can be seen from the above reaction, 1 mole of KCl is required to react with 1 mole of AgNO₃ and 1 mole of AgCl is formed, but only 0.75 mol of KCl. therefore we calculate according to the amount of KCl. that is, 0.75 mol of KCl reacts with 0.75 mol (an increase of 0.25 mol) of AgNO₃ to form 0.75 mol of AgCl.

Calculate the mass of AgCl formed:

0.75*143.5=134.625gr

Answer: 0.75mol or 134.625 gr of AgCl are formed