Answer to Question #122032 in General Chemistry for Ajiboye mosturah

Question

When 50cm of a saturated solution of knO3 at 25°c was evaporated to dryness ,10g of dry salt was obtained what is the solubility of knO3 at 25°c (knO3=101)

Answer 1

1mol =100cm³

? = 50cm³

50/1000 =0.05 mol

1mol = 101 g

0.05mol =[ 0.05][101]

=5.05g

{[10][100]}/[5.05]

=198g/cm³