Answer to Question #119918 in General Chemistry for moza

Question

2KClO3 → 2KCl + 3O2
What is the % yield of the above reaction if only 45 g of oxygen is produced from 122 g of potassium chlorate?

Answer 1

First the theoretical yield of O₂ should be determined.

n (KClO₃) = 122g / 122g/mol = 1 mol

According to the reaction, n (O₂) = 3/2 x n (KClO₃) = 1.5 mol

m (O₂) = 1.5 mol x 32 g/mol = 48 g - theoretical yield.

%yield = (actual yield / theoretical yield) x 100% = 45/48 x 100% = 93.75%.

Answer: 93.75%