Answer to Question #118281 in General Chemistry for Viola

Question

When 23.2 mL of 0.100 M NaOH was reacted with 20.3 mL of H2SO4 of unknown molarity, the final solution was 0.035493 M in H2SO4. What is the molarity of the original H2SO4 solution?

The equation for the reaction is:
2 NaOH + H2SO4 → Na2SO4 + 2 H2O

Answer 1

The equation is:

$1000*(20.3*C/1000-2*23.2*0.100/1000)/(20.3+23.2) =0.035493 M =>$

$=> C =C_0 (H_2SO_4 )=0.304629 M$