n(Zn)
n=mM=3.465.38=0.05n=\frac{m}{M}=\frac{3.4}{65.38}=0.05n=Mm=65.383.4=0.05
n(HCL)
n=mM=936.4609=0.24n=\frac{m}{M}=\frac{9}{36.4609}=0.24n=Mm=36.46099=0.24
decide further on zinc, in shortage
n(H2)=n(Zn)=0.05
m(H2)
m=n×M=0.05×2.016=0.1m=n\times M=0.05\times2.016=0.1m=n×M=0.05×2.016=0.1 g
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