Answer to Question #118020 in General Chemistry for Sophia

Question

What is the molarity of OH− in solutions
with an H3O+ concentration of 0.00037 mol/L?
Answer in units of mol/L

Answer 1

Concentration of $H_3O^+=0.00037\frac{mol}{L}$

$pH=-log(0.00037)=3.43$

$pOH=14-3.43=10.57$

Hence, molarity of $OH^-=antilog(-10.57)=0.269\times10^{-10}\frac{mol}{L}$