Here the pressure remains constant zo we have to calculate only the change of volume with respect to temperature.
From Charl's Law
V1/ T1 = V2 / T2
Here
V1 = 0.300 L
T1= 10°C
= 283 K
T2 = 30° C
= 303 K
So final volume, V2 will be
V2 = (0.300 × 303)/ 283
= 0.32 L
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