M(H2) = 2.016 g/mol;
Proportion according to reaction:
3 moles (H2) – 2 moles (NH3)
x moles – 4 moles
x = 6 moles;
m = n×M;
m(H2) = 6 moles × 2.016 g/mol = 12.096 g
Answer: 12.1 g
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