1) HCl + NaOH → NaCl + H2O
Moles (HCl) = Conc x Vol/1000 = 2.0*100/1000 = 0.2 moles
Moles (NaOH) = Conc x Vol/1000 = 2 * 100/1000 = 0.2 moles
2) Q = m*c*ΔT
Total mass of "water" = 200 g
ΔT = 35 - 29 = 6 K
Q= 200*6*4.2=5.04 kJ
3) ΔHneutralisation =Q/moles of water made
ΔHneutralisation=5.04/0.2 = 25.2 kJ
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