Answer to Question #117057 in General Chemistry for Shania kumar

Question

150 g of aluminium is cooled from 290K to 273K. Calculate the entropy change. Specific heat of aluminium is 0.902 J.

Answer 1

change is entropy can be calculated by following formula

∆S=m*c*ln(T2/T1)

here given mass of aluminium is 150g

c= 0.902 J/gmK

T2= 273 K

T1= 290 K

∆S= 150*0.902*ln(273/290)

∆S=-8.17J/K