Let final temperature be TTT ,
Net heat supplied=mc△T=mc\triangle T=mc△T
24.1 KJ=24100 J=250×0.902×(T−15.1)24.1\ KJ=24100\ J=250\times 0.902\times (T-15.1)24.1 KJ=24100 J=250×0.902×(T−15.1)
T−15.1=106.87°C ⟹ T=121.87°CT-15.1=106.87\degree C\implies T=121.87\degree CT−15.1=106.87°C⟹T=121.87°C
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments