Answer to Question #116746 in General Chemistry for Aaron

Question #116746
Calculate how many grams of KO2LAiD are needed to make 43.0 mL of a 0.25 M solution.
1
Expert's answer
2020-05-19T08:59:03-0400

1)

n(KAl(OH)2)=Vc=0.25M0.043L=0.01075moln(KAl(OH)_2) = Vc = 0.25M*0.043L = 0.01075 mol

2)


m(KAl(OH)2)=0.01075mol93.06138g/mol=1.00041gm(KAl(OH)_2) = 0.01075mol*93.06138g/mol = 1.00041 g


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