Answer to Question #116746 in General Chemistry for Aaron
Calculate how many grams of KO2LAiD are needed to make 43.0 mL of a 0.25 M solution.
1
2020-05-19T08:59:03-0400
1)
n(KAl(OH)2)=Vc=0.25M∗0.043L=0.01075mol 2)
m(KAl(OH)2)=0.01075mol∗93.06138g/mol=1.00041g
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