Answer to Question #116684 in General Chemistry for lin

Question

What volume of carbon dioxide ( at S.T.P.) is produced during the complete combustion of 200g of methane with a 90% Purity?

Answer 1

At first we have to calculate mass and amount of pure methane (CH₄):

m(pure CH₄) = 200 g *0.9 = 180 g - mass of pure methane.

n(pure CH₄) = 180 g/16.04 g/mol = 11.22 mol - amount of pure methane

Then, according to reaction:

CH₄ + 2O₂ = CO₂ + 2H₂O

We can find out that amount of carbon dioxide produced will be equal to amount of pure methane (because coefficients in equation before them is 1). Therefore n(CO₂) = 11.22 mol.

Finally,we need to calculate volume of CO₂:

V(CO₂) = n(CO₂)*V_molar, V_molar of gases is known and equal to 22.4 L/mol

So, V(CO₂) = 11.22 mol * 22.4 L/mol = 251.33 L

Answer: Volume of carbon dioxide is 251.33 L.