Answer to Question #116422 in General Chemistry for Gracyn

Question

how many joules are needed to warm 56.1 grams of water from 14*C to 22.5*C
the specific heat of the water is 4.18 J/g* C

Answer 1

∆H = mC∆T

m = 56.1 g;

C = 4.18 J/(g×°C);

∆T = 22.5 - 14 = 8.5 °C;

∆H = 56.1 g × 4.18 J/(g×°C) × 8.5 °C = 1993.2 J;

Answer: 1.99 kJ