"MnO_2(s) + 4HCl(aq) \u2192 Cl_2(g) + MnCl_2(aq) + 2H_2O(l)"
from the above equation we can see that for every 4 mole of HCl consumed 1 mole of chlorine gas is produced.
total moles of HCl ="\\frac{212}{36.5}"=5.8
moles of chlorine gas produced = "\\frac{5.8}{4}=1.45"
grams of chlorine produced =1.45"\\times"71=102.95
As the percent yield is 91 here so finally amount of chlorine gas obtained ="\\frac{91}{100}\\times102.95=93.7 g"
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