Answer to Question #116315 in General Chemistry for Nashrah Ahsan

Question

Calculate how many grams of KO2LAiD are needed to make 43.0 ml of 0.25 M solution

Answer 1

0.25M means 0.25moles per 1000ml.

Then (43/1000)* 0.25 = 0.01075 moles are in 43ml of solution.$Mass = moles*rfm$

Mass =0.01075 *71.1 = 0.76g