Question

what volume will 2.5 miles of nitrogen occupy at a pressure of .725 atm and a temperature of 23°C

Answer 1

Given,$P=0.725 \ atm,V=?,n=2.5,T=23\degree C=273+23=296K,R=0.0821$

Using ideal gas equation,$PV=nRT$

$0.725\times V=2.5\times 0.0821\times 296\implies V=\frac{2.5\times 0.0821\times 296}{0.725}$ $=83.799\ L$