Question #115833
8.) Calculate the amount of H3O+ ions in a solution of 0.312 M NaOH.
1
Expert's answer
2020-05-19T08:43:57-0400

NaOH is strong base hence 100 % dissociation will take place hence

[OH-]=0.312

[H+][OH−]=10−14[H^+][OH^-]=10^{-14}

[H+]=10−140.312=3.2×10−14[H^+]=\frac{10^{-14}}{0.312}=3.2\times10^{-14}


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