Answer to Question #114878 in General Chemistry for mike

Question

Here is a balanced equation. Use it to answer the questions below.

2Pb(NO3)2

Answer 1

2Pb(NO3)2 ---> 2PbO + 4NO2 + O2

4 moles of nitrogen dioxide will be produced from 2 moles of lead(ll) nitrate

0.5 mole of oxygen will be produced from 1 mole of lead(ll) nitrate

The mass of PbO obtained from 200g of Pb(NO3)2:

M (PbO) = 223.20

M (Pb(NO3)2) = 331.21

x = 200* 223.20 / 331.21 = 134.78 g

If 130g of PbO are actually obtained when the experiment is done in the laboratory, the percentage yield is:

130 / 134.78 = 0.965 or 96.5%