2LiOH(s) + CO2(g) → Li2CO3(s) + H2O(l)
According to the reaction, the number of moles of the reactants must be equal. As a result, the mass of carbon dioxide can be calculated from the following equation:
m(LiOH) / [2 × Mr(LiOH)] = m(CO2) / Mr(CO2)
From here:
m(CO2) = m(LiOH) × Mr(CO2) / [2 × Mr(LiOH)] = 1.00 kg × 44 g/mol / [2 × 24 g/mol] = 0.917 kg = 917 g
Answer: 917 g
Comments
Leave a comment