Question

If i dilute 75mL of .41M CaF2 solution to a final volume of 375, what will be the molarity of the resulting solution?

Answer 1

1) $\nu$ (for the 1st solution) = $C•V$ = 41(M) • 0.075(L) = 3.08 mol ; the amount of substance from dilution doesn't change $\to$ $\nu(1)=\nu(2)$ = 3.08 mol

2)$C$ (for solution after dilution) = $\nu/V$ = 3.08(mol) / 0.375 (L) = 8.21 M

Answer: C (for the solution after dilution) = 8.21 M