applyingV1T1=V2T2applying \\\frac{V_1}{T_1}=\frac{V_2}{T_2}applyingT1V1=T2V2
40273−123=V2273+27\frac{40}{273-123}=\frac{V_2}{273+27}273−12340=273+27V2
V2=40×300/150=80mlV_2=40\times300/150=80 mlV2=40×300/150=80ml
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