Answer to Question #112934 in General Chemistry for Nathaly

Question

The unheated gas in the above system has a volume of 20.0 L at a temperature of 25.0 °C and a pressure of 1.00 atm. The gas is heated to a temperature of 100.0 °C while the volume remains constant. What is the pressure of the heated gas?

Answer 1

According to the combined gas law equation:

p₁V₁/T₁ = p₂V₂/T₂

where p₁ - initial pressure, V₁ - initial volume, T₁ - initial temperature, p₂ - final pressure, V₂ - final volume, T₂ - final temperature.

If the volume remains constant:

p₁/T₁ = p₂/T₂

From here, the pressure of the heated gas is:

p₂ = p₁T₂ / T₁

As T₁ = 25.0 °C = 298.15 K and T₂ = 100.0 °C = 373.15 K:

p₂ = 1.00 atm × 373.15 K / 298.15 K = 1.25 atm

Answer: 1.25 atm