Solution.
(CH3)3Ga + AsH3 "\\to" GaAs + 3CH4;
1 mol 1 mol 1 mol
m((CH3)3Ga) = 300g;
m(AsH3) = 200g;
"\\nu"((CH3)3Ga) = (300g"\\sdot" 1mol )/114.83g =3.92 mol;
"\\nu" (AsH3) = (200g "\\sdot" 1 mol)/77.95 g = 3.85 mol;
We use the given quantity of AsH3 ( the limiting reactant) to calculate the quantity of GaAs formed.
m(GaAs) = (3.85mol(AsH3)"\\sdot" 144.64g)/1 mol (AsH3) = 556.86 g;
The limiting reagent in a chemical reaction is the substance that is totally consumed when the chemical reaction is completed. The limiting reagent in this reaction is AsH3.
Answer: m(GaAs) = 556.86 g;
The limiting reagent in a chemical reaction is the substance that is totally consumed when the chemical reaction is completed. The limiting reagent in this reaction is AsH3.
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