Answer to Question #112230 in General Chemistry for cole

Question

What is the limiting reactant when 12.8 g of
CuO are exposed to 2.46 g of H2 according to
the equation
CuO(s) + H2(g) −→ Cu(s) + H2O(g) ?

Answer 1

When reacting with 1 mol of copper oxide, 1 mol of hydrogen reacts

n(CuO)=m/M=12,8g/79,5g/mol=0,16mol

n(H₂)=2,46g/2g/mol=1,23mol

Copper oxide is in short supply, therefore, it is a limiting agent.