Solution.
"\\nu((NH_4)_3PO_4) = 2.0 mol;"
"m = \\nu\\sdot M;"
"M(PO_4^3- ) = 31 + 16\\sdot4 = 95 g\/mol;"
"2.0 mol (NH_4)_3PO_4 contains 2.0mol PO_4^3-;"
"m(PO_4^3-) = 95 g\/mol \\sdot 2.0 mol = 190g;"
Answer: "m(PO_4^3-) = 190g."
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