Question

Calculate the final pressure inside a scuba tank after it cools from 175.5 °C to 25.5 °C. The initial pressure in the tank is 130.0 atm. Use Gay-Lussac’s Law.

Answer 1

Gay-Lussac’s Law is $V/T=const$

So $V_1/T_1=V_2/T_2$ , T - temperature(K), V - volume.

Express the second volume: $V_1T_2/T_1=V_2$

T₁=175,5oC=448,5K

T₂=25,5oC=298,5K

V₂=130,0atm*298,5K/448,5K=86,5atm

Answer:86,5atm.