Answer to Question #111860 in General Chemistry for Savannah Williams

Question

Calculate the density of nitrogen gas at 120 degrees Celsius and a pressure of 700mmHg

Answer 1

T = 120 ⁰C = 273+120 K = 393 K

P = 700 mmHg = 101325/760*700 Pa = 93326 Pa

M(N₂) = 28 g/mol

According to Ideal gas law,

$PV = nRT\\ \rho = {\frac {m}{V}}={\frac {nM}{V}}\\ P={\frac {n}{V}}RT\\ {\frac {n}{V}}={\frac {P}{RT}}\\ \rho = {\frac {P}{RT}}M={\frac {93326}{8.314*393}}*28 =800$ g/m³ = 0.8 g/L