n (NaOH) = 0.78 / 40 = 0,0195 mol
C = 0,0195 M
T = 21 + 273.15 = 296.15 K
NaOH = Na+ + OH- (2 ions, i = 2)
П = 2 * 0,0195 * 0.08206 * 296.15
П = 0,95 atm
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