1)because entalpy fundamental simple is zero. O2
2)dT=Q*C*m
dt=111.1*C
Final temperature:136,1C
3)CH4+O2=CO2+2H2O
1 mole CH4=>2 mole H2O, 36 g water.
2 mole CH4=>4 mole H2O, 72 g
4 mole CH4=>8 mole H2O, 144g
Mass of water:50+72 =122or 50+144=194
The C_water=1cal/g*C
deltaT=23*C
Qwater=dT*C*m =2806 cal(or4462l
Qcalomiter=394703cal
Summ=397509 (or 399165)
Entalpy combustion reaction is Q/nmoles
1)198754,5=198,75Kcal/mol 2)99791,25cal=99,79Kcal/mol
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