CxHy + O2 = xCO2 + y/2 H2O
If we burn 1 mol of certain hydrocarbon, we would get x mol of CO2 and y/2 mol of H2O.
During combustion, we received 54/18 = 3 mol of water and 89.6/22.4 = 4 mol CO2.
The hydrocarbon should be C4H6 (option D).
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