Answer to Question #110761 in General Chemistry for Mahmoud Rabah

Question

What is the boiling point of a solution that contains 1.25 mol CaCl2 in 1400 g of water

Answer 1

Law of solutions (Raul's) dT_{boillingpoint}=E $\mu$

The molality is n(CaCl₂)/m(H2O)=0.892 mole/kg

dT=0.52*0.892=0.464 C