Answer to Question #110407 in General Chemistry for Aseel

Question

Calculate the weight of glucose equivalent to the criteria for Fehling's solution, knowing that the glucose solution is 10 milliliters

Answer 1

Sources indicate that 1cm3 (1 mL) of Fehling’s solution is equivalent to 0.005 g of glucose. So 10 mL would be equivalent to 0.05 g of glucose.