Solution.
"\\Delta T = Kb \\times Cm"
"Cm = \\frac{n(NaOH)}{m(H2O)}"
Cm = 0.25 mol/kg
"Cm = 0.25 \\times 2 = 0.50 \\ mol\/kg"
"\\Delta T = 0.50 \\times 0.52 = 0.26"
To = 100 oC
"T(fin.) = 100 + 0.26 = 100.26 ^oC = 100.3^oC"
Answer:
b
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